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22 articles found matching your search request ‘midrange’…

• New Math Functions in Java

  …midrange = (maxValue + minValue)/2.0; … if (z >= minValue && z < midrange) … if (z >= midrange && z < maxValue) … maxValue(a,b,c), midleValue(a,b,c), midrange1, midrange2 … evaluate midrange1 and midrange2 …

  Posted Jan 8, 02:37 PM, Author Dr. Candida Ferreira

• New Math Functions in VB.Net

  …evaluate minValue(x,y), maxValue(x,y) and midrange … midrange As Double = (maxValue + minValue)/2.0 … z >= minValue And z < midrange Then … z >= midrange And z < maxValue Then … maxValue(a,b,c), midleValue(a,b,c), midrange1, midrange2 …

  Posted Jan 7, 09:22 PM, Author Dr. Candida Ferreira

• New Math Functions in JavaScript

  …= Math.max(x,y);     var midrange = (maxValue + minValue)/2.0; … if (z >= minValue && z < midrange) … = 1.0;     else if (z >= midrange && z < maxValue) … maxValue(a,b,c), midleValue(a,b,c), midrange1, midrange2     // … = b;     // evaluate midrange1 and midrange2     var …

  Posted Jan 9, 03:48 PM, Author Dr. Candida Ferreira

• New Math Functions in Go

  …evaluate minValue(x,y), maxValue(x,y) and midrange     minValue := math.Min(x,y) … := math.Max(x,y)     midrange := (maxValue + minValue)/2.0 … else if z >= minValue && z < midrange { … = 1.0     } else if z >= midrange && z < maxValue { … maxValue(a,b,c), midleValue(a,b,c), midrange1, midrange2     // …

  Posted Jan 30, 05:56 PM, Author Dr. Candida Ferreira

• New Math Functions in Ada

  …        midrange: long_float; … evaluate minValue(x,y), maxValue(x,y) and midrange …         midrange := (maxValue + minValue)/2.0; … elsif ((z >= minValue) and then (z < midrange)) then … elsif ((z >= midrange) and then (z < maxValue)) then …

  Posted Jan 13, 10:39 PM, Author Dr. Candida Ferreira

• New Math Functions in Pascal

  …var     minValue, maxValue, midrange: real; begin     { evaluate … minValue(x,y), maxValue(x,y) and midrange }     minValue := x; …     midrange := (maxValue + minValue)/2.0; … if ((z >= minValue) and (z < midrange)) then … := 1.0     else if ((z >= midrange) and (z < maxValue)) then …

  Posted Jan 14, 07:21 PM, Author Dr. Candida Ferreira

• Function Design: 4-Output Mapper Functions

  …    // evaluate min(x0,x1), max(x0,x1) and midrange     double min = x[0];    double max = x[1];     …      min = x[1];        max = x[0];    }    double midrange = (max + min)/2.0;    double output = 0.0;    if …     else if (x[2] >= min && x[2] < midrange)        output = 1.0;    else if (x[2] >= … midrange && x[2] < max)        output = 2.0;     …

  Posted Dec 17, 11:00 PM, Author Dr. Candida Ferreira

• New Math Functions in Visual Basic

  …evaluate minValue(x,y), maxValue(x,y) and midrange     Dim minValue As Double … If     Dim midrange As Double     midrange = … z >= minValue And z < midrange Then … = 1.0     ElseIf z >= midrange And z < maxValue Then … maxValue(a,b,c), midleValue(a,b,c), midrange1, midrange2     ' …

  Posted Jan 4, 09:50 PM, Author Dr. Candida Ferreira

• New Math Functions in Excel VBA

  …evaluate minValue(x,y), maxValue(x,y) and midrange     Dim minValue As Double … If     Dim midrange As Double     midrange = … z >= minValue And z < midrange Then … = 1     ElseIf z >= midrange And z < maxValue Then … maxValue(a,b,c), midleValue(a,b,c), midrange1, midrange2     ' …

  Posted Jan 2, 09:58 PM, Author Dr. Candida Ferreira

• New Math Functions in Fortran

  …evaluate minValue(x,y), maxValue(x,y) and midrange … :: midrange …         midrange = (maxValue + minValue)/2.0 … if ((z >= minValue) .and. (z < midrange)) then … if ((z >= midrange) .and. (z < maxValue)) then …

  Posted Jan 10, 10:42 PM, Author Dr. Candida Ferreira

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